发布网友 发布时间:2024-10-23 07:07
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热心网友 时间:4分钟前
(1) ∆ = 4(k - 1)² - 4(k² - 1) = 4(k² - 2k + 1 - k² + 1) = 8(1 - k) > 0k < 1(2) x₁x₂ = k² - 1 = 0, k = ±1k = 1: x² = 0, x₁ = x₂ = 0, 舍去k = -1: x²-4x = x(x - 4) = 0, x = 0, x = 4另一个根为4