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HttpClient在使用中有两个超时时间

2021-06-09 来源:乌哈旅游


HttpClient在使用中有两个超时时间,是一直接触和使用的,由于上次工作中使用httpClient造成了系统悲剧的情况,特地对它的两个超时时间进行了小小的测试,在这里记录下。

测试版本为HttpClient——3.1

一:连接超时:connectionTimeout

1:指的是连接一个url的连接等待时间。

2:设置方法为:

public class TestHttpClientMain {

/**

* @param args

*/

public static void main(String[] args) {

HttpClient client = new HttpClient();

HttpMethod method = new GetMethod(

\"http://test.com\");

client.getHttpConnectionManager().getParams()

.setConnectionTimeout(3000);

client.getHttpConnectionManager().getParams().setSoTimeout(3000);

try {

int statusCode = client.executeMethod(method);

System.out.println(statusCode);

byte[] responseBody = null;

responseBody = method.getResponseBody();

String result = new String(responseBody);

System.out.println(result);

} catch (HttpException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (IOException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

3:测试的时候,将url改为一个不存在的url:“http://test.com”

4:超时时间3000ms过后,系统报出异常。

org.apache.commons.httpclient.ConnectTimeoutException: The host did not accept the connection within timeout of 3000 ms

at

org.apache.commons.httpclient.protocol.ReflectionSocketFactory.createSocket(ReflectionSocketFactory.java:155)

at

org.apache.commons.httpclient.protocol.DefaultProtocolSocketFactory.createSocket(DefaultProtocolSocketFactory.java:125)

at

org.apache.commons.httpclient.HttpConnection.open(HttpConnection.java:707)

at

org.apache.commons.httpclient.HttpMethodDirector.executeWithRetry(HttpMethodDirector.java:387)

at

org.apache.commons.httpclient.HttpMethodDirector.executeMethod(HttpMethodDirector.java:171)

at

org.apache.commons.httpclient.HttpClient.executeMethod(HttpClient.java:397)

二:读取数据超时:soTimeout

1:指的是连接上一个url,获取response的返回等待时间

2:设置方法

public class TestHttpClientMain {

/**

* @param args

*/

public static void main(String[] args) {

HttpClient client = new HttpClient();

HttpMethod method = new GetMethod(

\"http://localhost:8080/firstTest.htm?method=test\");

client.getHttpConnectionManager().getParams()

.setConnectionTimeout(3000);

client.getHttpConnectionManager().getParams().setSoTimeout(2000);

try {

int statusCode = client.executeMethod(method);

System.out.println(statusCode);

byte[] responseBody = null;

responseBody = method.getResponseBody();

String result = new String(responseBody);

System.out.println(result);

} catch (HttpException e) {

// TODO Auto-generated catch block

e.printStackTrace();

} catch (IOException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

3:测试的时候的连接url为我本地开启的一个http://localhost:8080/firstTest.htm?method=test

url

在我这个测试url里,当访问到这个链接时,线程sleep一段时间,来模拟返回response超时。

@RequestMapping(params = \"method=test\") //<——②

public String testMethod(ModelMap model) {

try {

Thread.sleep(3000);

} catch (InterruptedException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

System.out.println(\"call testMethod method.\");

model.addAttribute(\"name\

return \"test\";

}

4:将读取response返回超时时间设的时间比那个sleep时间短之后,运行程序给出异常:

java.net.SocketTimeoutException: Read timed out

at java.net.SocketInputStream.socketRead0(Native Method)

at java.net.SocketInputStream.read(Unknown Source)

at java.io.BufferedInputStream.fill(Unknown Source)

at java.io.BufferedInputStream.read(Unknown Source)

at org.apache.commons.httpclient.HttpParser.readRawLine(HttpParser.java:78)

at org.apache.commons.httpclient.HttpParser.readLine(HttpParser.java:106)

at

org.apache.commons.httpclient.HttpConnection.readLine(HttpConnection.java:1116)

at

org.apache.commons.httpclient.HttpMethodBase.readStatusLine(HttpMethodBase.java:1973)

at

org.apache.commons.httpclient.HttpMethodBase.readResponse(HttpMethodBase.java:1735)

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